-2x^2+50=2

Solution for -2x^2+50=2 equation:

-2x^2+50=2

We move all terms to the left:

-2x^2+50-(2)=0

We add all the numbers together, and all the variables

-2x^2+48=0

a = -2; b = 0; c = +48;
Δ = b2-4ac
Δ = 02-4·(-2)·48
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*-2}=\frac{0-8\sqrt{6}}{-4}
=-\frac{8\sqrt{6}}{-4}
=-\frac{2\sqrt{6}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*-2}=\frac{0+8\sqrt{6}}{-4}
=\frac{8\sqrt{6}}{-4}
=\frac{2\sqrt{6}}{-1}
$